Tuesday, March 13, 2012

want to be a doctor?: CELL BIOLOGY UPTO CHROMOSOMES ASSIGNMENT

want to be a doctor?: CELL BIOLOGY UPTO CHROMOSOMES ASSIGNMENT

want to be a doctor?: NUCLEIC ACIDS AND CELL DIVISION

want to be a doctor?: NUCLEIC ACIDS AND CELL DIVISION

want to be a doctor?: TISSUES ASSIGNMENT

want to be a doctor?: TISSUES ASSIGNMENT

want to be a doctor?: INTERNAL ORGANISATION OF PLANTS-ASSIGNMENT

want to be a doctor?: INTERNAL ORGANISATION OF PLANTS-ASSIGNMENT

want to be a doctor?: PLANT ECOLOGY-ASSIGNMENT

want to be a doctor?: PLANT ECOLOGY-ASSIGNMENT

want to be a doctor?: GENETICS-ASSIGNMENT

want to be a doctor?: GENETICS-ASSIGNMENT

GENETICS-ASSIGNMENT

1 Among the following identify the Pea plant with only dominant characters.




Ans:Inflated green pods developed from axillary flowers
2 Arrange the following plants of Pea in a sequence of recessive to complete dominant features.
I. Short plants with rounded seeds, green cotyledons and Grey testa
II. Tall plants with wrinkled seeds, green cotyledons and Grey testa
III. Yellow ripe pods, yellow cotyledons, round seeds and white testa
IV. Green ripe pods with yellow cotyledons, round seeds developed on tall plats





Ans:II, I, III, IV
3 Total number of Pea varieties collected by Mendel was




Ans:34
4 Mendel’s experimental results were not confirmed by




Ans:Boveri
5 The term Genetics was given by




Ans:Bateson
6 Choose the correct statements
I. Mendel was the first to perform hybridization experiments
II. Mendel was the first person to consider the results of hybridization in terms of single traits.
III. Mendel counted and classified the progeny resulted from crosses in pea plants
IV. Mendel compared the proportions of his hybridization results with mathematical models.





Ans:all except I
7 [A]: Mendel identified Pea plants as suitable to carry out hybridization experiments
[R]: Pisum sativum has bisexual flowers that naturally cross fertilised





Ans:A is true but R is false
8 Select the correct characters shown by Pisum sativum
I. It is Annual
II. It can be grown and handled easily
III. It produces larger number of offspirings
IV. It has well defined characters





Ans:I, II, III, IV
9 Mendel’s experimental results were published as




Ans:Experiments in Plant hybridisation
10 Choose the correct statements with respect to Monohybrid crosses
I. Tall plants of parental generation do not have allele ‘t’.
II. Tall plants of F1 generation do not have allele ‘t’.
III. The plants of F2 generation without the allele ‘t’ and with only ‘t’ alleles exist in 1:1 ratio.
IV. The ratio between the tall plants of F2 and F1 generation is 3:4.





Ans:I, III, IV
11 Individuals of the following genotypes are not seen in P and F1 generations during dihybrid cross




Ans:TT rr
12 The assumptions made by Mendel through his experiments were sustained by the discovery of




Ans:Meiosis
13 Study the following table and choose the correct combination





Ans:All except II
14 In Mendels dihybrid cross F2 individuals with the following genotype are formed in 1:1:1:1 ratio




Ans:rr yy, rr YY, RR YY, RR yy
15 Arrange the following crosses in a sequence of gradual increase in the number of offspring with the genotype Rr Yy
I. Rr YY X rR yY
II. RR yy X rr YY
III. Rr YY X Rr Yy
IV. rr YY X RR Yy





Ans:III, I, IV, II
16 In the following crosses all the individuals formed will be having similar genotype
I. RR YY X rr yy
II. rr YY X RR yy
III. Rr YY X RR Yy
IV. Rr Yy X RR YY





Ans:I, II
17 Match the following





Ans:A - II, B - V, C - IV, D - I
18 Plants with similar forms of alleles on homologous chromosomes are




Ans:Dwarf pea plants
19 The ratio between the F2 plants of dihybrid cross with homologous and non-homologous alleles for both the traits is




Ans:1:1
20 When monohybrid crosses are made in Pea plants, the following fail to appear in F1 generation




Ans:Plants with terminal flowers
21 [A]: All F1 plants of Monohybrid cross are tall
[R]: F1 hybrids have the allele ‘t’.





Ans:Both A and R are true but R is not the correct explanation of A
22 Number of types of gametes formed by pea plant with genotype as AA, Tt, Yy, Rr is




Ans:8
23 Study the following with respect to Monohybrid cross and identify the suitable match





Ans:A - V, B - IV, C - II D - I
24 If a cross is made between between the pea plants with the genotypes as Rr Yy and rr Yy, the pea plants with the following genotypes can not be formed
I. rr yy
II. Rr YY
III. RR yy
IV. RR Yy





Ans:III and IV
25 In a dihybrid cross, the ratio between the phenotypically similar individuals of F1 and F2 generations is




Ans:16:9
26 Match the following





Ans:A - V, B - IV, C - II, D -I
27 Out of 16 outcomes of an event , in how many out comes there is formation of Mendelian recombinants in F2 generation of Dihybrid cross.




Ans:6
28 Choose from the following where the probability is 1/4.
I. Formation of gametes in F1 dihybrid with allele RY.
II. Formation of dwarf plants in F2 generation of Mendelian Monohybrid cross.
III. Formation of wrinkled seeds in F2 generation of Dihybrid cross.
IV. Formation of Round green seeds in F2 generation of Dihybrid cross.





Ans:All except IV
29 2Arrange the following crosses with gradual increase in the probability of formation of Round and yellow seeded plants
I. Ry Yy X rr yy
II. rr Yy X RR yy
III. RR Yy X RR Yy
IV. Rr Yy X RR YY





Ans:I, II, III, IV
30 Choose the set with mutually exclusive genotypic outcomes of an event for the formation of yellow seeds




Ans:YY ; Yy ; yY
31 Choose the crosses that show the probability of formation of heterozygous Yellow seeded plants is 1/2.
I. YY X Yy
II. Yy X Yy
III. yy X Yy





Ans:I, II, III
32 The probability of formation of yellow round seeded plants in F2 generation of dihybrid cross which do not show the genotype Yy Ry is




Ans:5/16
33 By using the probability law, this is the correct explanation for the formation of F2 individuals of dihybrid cross with the genotype rr Yy




Ans:1/4 X 1/2
34 This is the correct explanation for the probability of obtaining F1 generation plants of Dihybrid cross with Yy Rr genotypes




Ans:1 X 1
35 Choose the genotypes of Mendel’s dihybrid cross whose probability in F2 generation is 1/2.




Ans:None
36 In a trihybrid cross, what is the probability of obtaining plants with the genotype RR Tt yy in F2 generation




Ans:1/4 x 1/2 x 1/4
37 Study the following table and choose the correct combinations with respect to Mendel’s dihybrid cross





Ans:I and III
38 [A]: The probability of formation of F2 individuals of dihybrid cross with the genotype Rr YY is 1/8.
[R]: The probability of formation of F2 individuals of Monohybrid cross with genotype Rr is 1/4 and with YY is 1/4.





Ans:A is true but R is false
39 When a heterozygous sweet pea plant with blue flowers and long pollen grains is test crossed , The progeny will not be having the following genotype




Ans:RR r0r0
40 Chromosomal maps that show linked genes were prepared by




Ans:T.H. Morgan

PLANT ECOLOGY-ASSIGNMENT

1 Long and linear leaves are seen in




Ans:Potamogeton
2 Eichhornia has
i) Spongy stem
ii) Spongy petiole
iii) Balancing roots





Ans:i, ii and iii are correct
3 Leaves of these hydrophytes are relatively larger




Ans:Rooted hydrophytes with floating leaves
4 Assertion : Respirating roots of Jussiaea are adventitious.
Reason : Hydrophytes usually have adventitious roots.





Ans:Both A and R are true and R is the correct explanation of A
5 Assimilatory epidermis is present in




Ans:Vallisnaria
6 Relatively wider cortex is seen in the roots of




Ans:Asparagus
7 Sclerenchymatous hypodermis is seen in the leaves of




Ans:Pinus
8 Identify the plant whose leaf is extended throughout the depth of waterbody




Ans:Nelumbo
9 Assertion : Sagittara has poorly developed xylem.
Reason : Hydrophytes grow in water rich conditions.





Ans:Both A and R are true and R is the correct explanation of A
10 Assertion : Nymphaea is a hydrophyte.
Reason : It has astrosclereids.





Ans:Both A and R are true but R is not the correct explanation of A
11 Study the following

Identify the two correct items





Ans:i and ii
12 Sub-aerial modified stems have no contact with the soil in




Ans:Eichhornia
13 Hydrochory is shown by




Ans:Nymphaea
14 Sagittaria shows
i) Heterophylly
ii) Stoloniferous stem
iii) Hydrophily





Ans:i and ii
15 Both aerial and underwater roots are seen in




Ans:Jussiaea
16 Match the following and identify the correct match
A. Plant having contact with only water    I) Ranunculus
B. Plant always having contact with
 both water and soil only            II) Ceratophyllum
C. Plant always having contact with
 air and water                             III) Cyperus
D. Plant always having contact with
 air water and soil                     IV) Salvinia
                                     V) Potamogeton 





Ans:A-II, B-V, C-IV, D-I
17 The following plant has relatively more developed xylem




Ans:Typha
18 The hydrophyte with developed root caps is




Ans:Cyperus
19 All leaves of the plant are dissected and root like in




Ans:Ceratophyllum
20 Odum defined ecology as




Ans:Study of ecosystems
21 This plant has contact with neither atmosphere nor soil




Ans:Utricularia
22 Assertion : Pistia has root pocket.
Reason : All hydrophytes lack root caps.





Ans:A is true but R is false
23 Choose the correct statement




Ans:All hydrophytes have aerenchyma
24 Study the following

Identify the two correct items





Ans:iii and iv
25 This hydrophyte can effectively survive for some time in dry period




Ans:Cyperus
26 Match the following
A. Hydrilla I) Bulbs
B. Nymphaea II) Rhizome
C. Aloe        III) Bulbils
D. Agave IV) Fragmentation
                   V) Suckers





Ans:A - IV, B - II, C - V, D - III
27 Stem doesn’t store water in




Ans:Casuarina
28 Arrange the following hydrophytic plants in a sequence of plants ‘having contact with soil and water’, ‘with only water’, ‘with water and atmosphere’ and ‘with water’ and ‘soil and atmosphere’
i) Ceratophyllum
ii) Sagittaria
iii) Eichhornia
iv) Potamogeton





Ans:iv, i, iii, ii
29 Assertion : Tribulus usually grows in Arid zones.
Reason : Xerophytes can grow only in water scarcity conditions.





Ans:A is true but R is false
30 Assertion : Well developed root cap is seen in Cyperus.
Reason : It is an amphibious plant.





Ans:Both A and R are true and R is the correct explanation of A
31 Leaves of Potamogeton are




Ans:Linear
32 Match the following
A. Rootless hydrophyte                      I) Cyperus
B. Hydrophyte with horizontally
 growing stem                              II) Nelumbo
C. Epistomatous plant                     III) Ranunculus
D. Hydrophyte surviving in dry periods      IV) Wolffia
                                             V) Azolla 





Ans:A - IV, B - V, C - II, D - I
33 Assertion : Eichhornia root shows polyarch and exarch condition.
Reason : It is a hydrophyte.





Ans:Both A and R are true but R is not the correct explanation of A
34 Succulent xerophyte with epidermal cells storing water is




Ans:Peperomia
35 Leaves are not transluscent in




Ans:Pistia
36 Study the following

Identify the two correct items





Ans:i and iv
37 Hydrophyte with some aerial and with some underwater leaves




Ans:Salvinia
38 Assertion : Tribulus shows mesophytic characters.
Reason : It never faces water deficient conditions.





Ans:Both A and R are true and R is the correct explanation of A
39 Match the following and identify the correct match
A. Leaves with multilayered 
sclerenchymatous hypodermis    I)Tribulus
B. Leaves with multiple epidermis  II)Aloe
C. Stems with multilayered 
sclerenchymatous hypodermis       III)Nerium
D. Leaves with mucilaginous mesophyll IV)Pinus
                                         V)Casuarina





Ans:A-IV, B-III, C-V, D-II